A) \[\frac{14}{15}\]
B) \[\frac{4}{5}\]
C) 1
D) \[\frac{2}{\sqrt{5}}\]
Correct Answer: A
Solution :
for solid sphere \[\frac{1}{2}m{{v}^{2}}+\frac{1}{2}.\frac{2}{5}m{{R}^{2}}.\frac{{{V}^{2}}}{{{R}^{2}}}=mg{{h}_{sph.}}\] for solid cylinder \[\frac{1}{2}m{{v}^{2}}+\frac{1}{2}.\frac{1}{2}m{{R}^{2}}.\frac{{{V}^{2}}}{{{R}^{2}}}=mg{{h}_{cyl.}}\] \[\Rightarrow \]\[\frac{{{h}_{sph.}}}{{{h}_{cyl.}}}=\frac{7/5}{3/2}=\frac{14}{15}\]You need to login to perform this action.
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