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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Afternoon)

  • question_answer
    If a point R(4,y,z) lies on the line segment joining the points P(2,-3,4) and Q(8,0,10), then the distance of R from the origin is :                                                                                        [JEE Main 8-4-2019 Afternoon]

    A) \[2\sqrt{14}\]

    B) 6

    C) \[\sqrt{53}\]                

    D) \[2\sqrt{21}\]

    Correct Answer: A

    Solution :

    \[\frac{4}{2}=\frac{-y}{y+3}=\frac{10-z}{z-4}\] \[\Rightarrow \]\[z=6\And y=-2\] \[\Rightarrow \]\[R(4,-2,6)\] dist. from origin \[=\sqrt{16+4+36}=2\sqrt{14}\]  


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