A) 1st and 2nd quadrants
B) 4th quadrant
C) 1st, 2nd and 4th quadrant
D) 1st quadrant
Correct Answer: A
Solution :
Now,\[\left| \frac{15-3t}{5} \right|=|t|\] \[\Rightarrow \]\[\frac{15-3t}{5}=t\]or\[\frac{15-3t}{5}=-t\] \[\therefore \]\[t=\frac{15}{8}\]or\[t=\frac{-15}{2}\] So, \[P\left( \frac{15}{8},\frac{15}{8} \right)\in {{\text{I}}^{\text{st}}}\]quadrant or \[P\left( \frac{-15}{2},\frac{15}{2} \right)\in \text{I}{{\text{I}}^{\text{nd}}}\]quadrantYou need to login to perform this action.
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