A) \[\frac{64}{17}\]
B) \[\frac{2}{17}\]
C) \[\frac{128}{17}\]
D) \[\frac{4}{17}\]
Correct Answer: B
Solution :
\[4{{a}^{2}}+{{b}^{2}}=8\] ....(a) also\[{{\left. \frac{dy}{dx} \right)}_{(1,2)}}=-\frac{4x}{y}=-2\] \[\Rightarrow \]\[-\frac{4a}{b}=\frac{1}{2}\] \[b=-8a\] \[\Rightarrow \]\[{{b}^{2}}=64{{a}^{2}}\] \[68{{a}^{2}}=8\] \[{{a}^{2}}=\frac{2}{17}\]You need to login to perform this action.
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