A) 3
B) 2
C) 1
D) 1.5
Correct Answer: B
Solution :
\[{{n}_{eq.}}KMn{{O}_{4}}={{n}_{eq.}}[Fe{{C}_{2}}{{O}_{4}}+F{{e}_{2}}{{({{C}_{2}}{{O}_{4}})}_{3}}\]\[+FeS{{O}_{4}}]\] or\[n\times 5=1\times 3+1\times 6+1\times 1\] \[\therefore \]\[n=2\] Correct option : (b)
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