A) less than 2
B) greater than 3 but less than 4
C) greater than 4
D) greater than 2 but less than 3
Correct Answer: B
Solution :
Now,\[\overrightarrow{MP}.\left( 10\hat{i}-7\hat{j}+\hat{k} \right)=0\]\[\Rightarrow \]\[\lambda =\frac{1}{2}\] \[\therefore \] Length of perpendicular \[(=PM)=\sqrt{0+\frac{1}{4}+\frac{49}{4}}\] \[=\sqrt{\frac{50}{4}}=\sqrt{\frac{25}{2}}=\frac{5}{\sqrt{2}},\] which is greater than 3 but less than 4.You need to login to perform this action.
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