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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Morning)

  • question_answer
    All possible numbers are formed using the digits 1, 1, 2, 2, 2, 2, 3, 4, 4 taken all at a time. The number of such numbers in which the odd digits occupy even places is :                     [JEE Main 8-4-2019 Morning]

    A) 175                 

    B) 162

    C) 160                 

    D) 180

    Correct Answer: D

    Solution :

    Number of such numbers  \[{{=}^{4}}{{C}_{3}}\times \frac{3!}{2!}\times \frac{6!}{2!4!}=180\]


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