A) \[\frac{2}{\ell n2}\]
B) \[\ell n2\]
C) \[2\ell n2\]
D) \[\frac{1}{2}\ell n2\]
Correct Answer: C
Solution :
\[LIdI={{I}^{2}}R\] \[L\times \frac{E}{10}\left( -{{e}^{-t/2}} \right)\times \frac{-1}{2}=\frac{E}{10}\left( 1-{{e}^{-t/2}} \right)\times 10\] \[{{e}^{-t/2}}=1-{{e}^{-t/2}}\] \[t=2\ell n2\]You need to login to perform this action.
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