I. \[n=4,l=2,{{m}_{l}}=2,{{m}_{s}}={\scriptscriptstyle 1\!/\!{ }_2}\] |
II. \[n=3{{,}_{l}}=2,{{m}_{l}}=1,{{m}_{s}}=+{\scriptscriptstyle 1\!/\!{ }_2}\] |
III. \[n=4{{,}_{l}}=1,{{m}_{l}}=0,{{m}_{s}}=+{\scriptscriptstyle 1\!/\!{ }_2}\] |
IV. \[n=3{{,}_{l}}=1,{{m}_{l}}=1,{{m}_{s}}={\scriptscriptstyle 1\!/\!{ }_2}\] |
The correct order of their increasing energies will be - |
A) \[IV<III<II<I\]
B) \[IV<II<III<I\]
C) \[~I<II<III<IV\]
D) \[I<III<II<IV\]
Correct Answer: B
Solution :
According to \[(n+\ell )\] rule: \[3p<3d<4p<4d\] Correct option: (b)You need to login to perform this action.
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