A) \[\frac{12}{5}\Omega \]
B) \[\frac{5}{3}\Omega \]
C) \[\frac{5}{2}\Omega \]
D) \[\frac{7}{2}\Omega \]
Correct Answer: B
Solution :
\[R=\frac{\rho {{\ell }^{2}}}{A\ell D}d=\frac{\rho d{{\ell }^{2}}}{m}\] \[R\propto {{\ell }^{2}}\] \[R=12\Omega \](new resistance of wire) \[{{R}_{1}}=2\Omega \,\,\,\,{{R}_{2}}=10\Omega \] \[{{R}_{eq}}=\frac{10\times 2}{10+2}=\frac{5}{3}\Omega .\]You need to login to perform this action.
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