A) bauxite
B) siderite
C) calamine
D) malachite
Correct Answer: A
Solution :
1. Bauxite-\[Al{{O}_{x}}{{(OH)}_{3-2x}}\]where \[0<x<1\] |
2. Siderite - \[FeC{{O}_{3}}\] |
3. Calamine - \[ZnC{{O}_{3}}\] |
4. Malachite - \[CuC{{O}_{3}}.Cu{{(OH)}_{2}}\] |
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