A) 0.12 K
B) 0.36 K
C) 0.18 K
D) 0.24 K
Correct Answer: B
Solution :
\[{{K}_{f}}=4\,K-kg/mol\] \[m=0.03\,mol/kg\] \[i=3\] \[\Delta {{T}_{f}}=i{{K}_{f}}\times m\] \[\Delta {{T}_{f}}=3\times 4\times 0.03=0.36K\]You need to login to perform this action.
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