A) \[8\sqrt{3}\]
B) \[4\sqrt{3}\]
C) \[10\sqrt{5}\]
D) \[8\sqrt{5}\]
Correct Answer: D
Solution :
\[SOR=\frac{3}{{{m}^{2}}+1}\Rightarrow {{(S.O.R)}_{\max }}=3\] when\[m=0\] \[\alpha +\beta =3\] \[\alpha \beta =1\] \[|{{\alpha }^{3}}-{{\beta }^{2}}|=||\alpha -\beta |({{\alpha }^{2}}+{{\beta }^{2}}+\alpha \beta )|\] \[\left| \sqrt{\alpha -\beta {{)}^{2}}-\alpha \beta }({{(\alpha +\beta )}^{2}}-\alpha \beta ) \right|\] \[=\left| \sqrt{9-4}(9-1) \right|\] \[=\sqrt{5}\times 8\]You need to login to perform this action.
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