A) 6
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
\[{{A}^{T}}A=3{{I}_{3}}\] \[8{{x}^{2}}=3\] \[6{{y}^{2}}=3\] \[{{x}^{2}}=3/8\] \[{{y}^{2}}=1/2\] \[x=\pm \sqrt{\frac{3}{8}};y=\pm \sqrt{\frac{1}{2}}\]You need to login to perform this action.
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