A) \[15\times {{10}^{8}}N\]
B) \[35\times {{10}^{8}}N\]
C) \[10\times {{10}^{8}}N\]
D) \[20\times {{10}^{8}}N\]
Correct Answer: D
Solution :
Force on the surface (25% reflecting and rest absorbing) \[F=\frac{25}{100}\left( \frac{2I}{C} \right)+\frac{75}{100}\left( \frac{I}{C} \right)=\frac{125}{100}\left( \frac{I}{C} \right)\] \[=\frac{25}{100}\times \left( \frac{50}{3\times {{10}^{8}}} \right)=20.83\times {{10}^{-8}}N.\]You need to login to perform this action.
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