A) \[\left\{ -\frac{1}{3},-1 \right\}\]
B) \[\left\{ \frac{1}{3},-1 \right\}\]
C) \[\left\{ -\frac{1}{3},1 \right\}\]
D) \[\left\{ \frac{1}{3},1 \right\}\]
Correct Answer: C
Solution :
\[\left( 1 \right)=112=2\] \[\left( 1 \right)=11+2=0\] \[m=\frac{f(1)-f(-1)}{1+1}=\frac{-2-0}{2}=-1\] \[\frac{dy}{dx}=3{{x}^{2}}-2x-2\] \[3{{x}^{2}}-2x-2=-1\] \[\Rightarrow 3{{x}^{2}}-2x-1=0\] \[\Rightarrow (x-1)(3x+1)=0\] \[\Rightarrow x=1,-\frac{1}{3}\]You need to login to perform this action.
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