A) \[N{{O}_{2}}<{{N}_{2}}{{O}_{3}}<NO<{{N}_{2}}O\]
B) \[N{{O}_{2}}<NO<{{N}_{2}}{{O}_{3}}<{{N}_{2}}O\]
C) \[{{N}_{2}}O<{{N}_{2}}{{O}_{3}}<NO<N{{O}_{2}}\]
D) \[{{N}_{2}}O<NO<{{N}_{2}}{{O}_{3}}<N{{O}_{2}}\]
Correct Answer: D
Solution :
Correct order of oxidation state of nitrogen in oxides of nitrogen is following \[\overset{+1}{\mathop{{{N}_{2}}}}\,O<\overset{+2}{\mathop{N}}\,O<\overset{+3}{\mathop{{{N}_{2}}}}\,{{O}_{3}}<\overset{+4}{\mathop{N}}\,{{O}_{2}}\]
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