A) 25
B) 24
C) 20
D) 22
Correct Answer: A
Solution :
\[{{y}^{2}}=4ax=16x\Rightarrow a=4\] \[A(1,4)\Rightarrow 2.4{{t}_{1}}=4\Rightarrow {{t}_{1}}=\frac{1}{2}\] \[\therefore \] length of focal chord\[=a{{\left( t+\frac{1}{t} \right)}^{2}}\] \[=4{{\left( \frac{1}{2}+2 \right)}^{2}}=4.\frac{25}{4}=25\]You need to login to perform this action.
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