A) \[\frac{10}{3}\]
B) \[\frac{9}{2}\]
C) \[\frac{31}{6}\]
D) \[\frac{13}{6}\]
Correct Answer: B
Solution :
\[{{x}^{2}}\le y\le x+2\] \[{{x}^{2}}=y;y=x+2\] \[{{x}^{2}}=x+2\] \[{{x}^{2}}-x-2=0\] \[(x-2)(x-1)=0\] \[x=2,-1\] Area,\[=\int\limits_{-1}^{2}{(x+2)}-{{x}^{2}}dx=\frac{9}{2}\]You need to login to perform this action.
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