A) \[\sqrt{\frac{30}{2}}\]
B) \[\frac{\sqrt{20}}{3}\]
C) \[\frac{\sqrt{30}}{2}\]
D) \[\sqrt{30}\]
Correct Answer: D
Solution :
\[mg\frac{L}{2}\,sin\,30{}^\circ \text{ }=\text{ }\frac{1}{2}\text{ }I{{\omega }^{2}}\] \[\frac{mgL}{4}=\frac{1}{2}\,\times \,\frac{1}{3}\,m{{L}^{2}}{{\omega }^{2}}\] \[{{\omega }^{2}}\,=\,\frac{3g}{2\,L}\] \[\omega \,=\,\sqrt{30}\,\,rad/s\]You need to login to perform this action.
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