JEE Main & Advanced
JEE Main Paper (Held On 09-Jan-2019 Evening)
question_answer
The number of natural numbers less than 7,000 which can be formed by using the digits 0, 1, 3, 7, 9 (repetition of digits allowed) is equal to:
[JEE Main Online Paper (Held On 09-Jan-2019 Evening]
A)372
B) 375
C) 250
D) 374
Correct Answer:
D
Solution :
There are 3 ways to fill I position (0, 1, 3) for remaining digits there are 5 ways hence ans \[=\text{ }3.\text{ }5.\text{ }5.\text{ }5-1\text{ }(0000\] not included) \[=375-1=374\]