A) \[\tan \,\theta \,\,=\,\,\frac{1}{3}\]
B) \[\tan \,\theta \,\,=\,\,\frac{1}{2}\]
C) \[\tan \,\theta \,\,=\,\,\frac{2}{\sqrt{3}}\]
D) \[\tan \,\theta \,\,=\,\,\frac{1}{2\sqrt{3}}\]
Correct Answer: A
Solution :
\[mg\text{ }\frac{a}{2}\,{{d}_{1}}=\,\,mg{{d}_{2}}\] \[mg\frac{a}{2}\,\sin \,\theta \,\,\,=\,\,\,mg\,(\frac{a}{2}\,\cos \,\theta \,\,-\,\,a\sin \,\theta )\] \[\frac{\sin \,\theta }{2}\,\,=\,\,\frac{\cos \,\theta }{2}\,\,-\,\sin \,\theta \] \[\frac{3}{2}\,\sin \,\theta \,\,=\,\,\frac{\cos \,\theta }{2}\] \[\tan \,\theta \,\,=\,\,\frac{1}{3}\]You need to login to perform this action.
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