[JEE Main Online Paper (Held On 09-Jan-2019 Morning]
A) P
B) \[{{P}^{1/2}}\]
C) \[{{P}^{2}}\]
D) \[{{P}^{1/4}}\]
Correct Answer: B
Solution :
\[\frac{x}{m}\,\,=\,\,k(P){{\,}^{1/n}}\] \[\frac{x}{m}\,\,=\,\,\log \,\,k\,\,+\,\frac{1}{n}\,\log \,\,P\] Slope \[=\,\,\frac{1}{n}\] From graph, slope = \[\frac{1}{2}\] \[\Rightarrow \,\,\,\,n=2\,\,\Rightarrow \,\,\frac{x}{m}\,\,\propto \,\,{{(P)}^{1/2}}\]
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