A) \[\left( 3,\text{ }\infty \right)\]
B) (1, 3/2]
C) (3/2, 2]
D) (2, 3]
Correct Answer: A
Solution :
\[si{{n}^{2}}\,\theta \,\,=\,\,co{{s}^{2}}\theta \,\,({{e}^{2}}\,-1)\] \[{{\tan }^{2}}\,\theta \,\,=\,\,{{e}^{2}}\,\,-1\] \[1\text{ }+\text{ }ta{{n}^{2}}\theta \text{ }=\text{ }{{e}^{2}}\]You need to login to perform this action.
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