A) \[4;1\times {{10}^{8}}Hz\]
B) \[0.25;1\times {{10}^{8}}Hz\]
C) \[4;2\times {{10}^{8}}Hz\]
D) \[0.25;\,2\times {{10}^{8}}Hz\]
Correct Answer: D
Solution :
\[{{f}_{m}}=100MHz={{10}^{8}}Hz,\]\[{{({{V}_{m}})}_{0}}=100V\] \[{{f}_{c}}=300GHz\] \[,{{({{V}_{c}})}_{0}}=400V\] Modulaton Index \[=\frac{{{({{V}_{m}})}_{0}}}{{{({{V}_{c}})}_{0}}}=\frac{100}{400}=\frac{1}{4}=0.25\] Upper band frequency (UBF) \[={{f}_{c}}+{{f}_{m}}\] Lower band frequency (LBF) \[={{f}_{c}}-{{f}_{m}}\] \[\therefore UBF-LBF=2{{f}_{m}}=2\times {{10}^{8}}Hz\]You need to login to perform this action.
You will be redirected in
3 sec