A) \[\frac{11}{10\lambda }\]
B) \[\frac{1}{9\lambda }\]
C) \[\frac{1}{10\lambda }\]
D) \[\frac{1}{11\lambda }\]
Correct Answer: B
Solution :
\[{{N}_{1}}={{N}_{0}}{{e}^{-10\lambda t}}\] \[{{N}_{2}}={{N}_{0}}{{e}^{-\lambda t}}\] \[\frac{1}{e}=\frac{{{N}_{1}}}{{{N}_{2}}}={{e}^{-9\lambda t}}\] \[\Rightarrow 9\lambda t=1\] \[t=\frac{1}{9\lambda }\]You need to login to perform this action.
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