A) \[1\Omega \]
B) \[1.5\Omega \]
C) \[0\Omega \]
D) \[0.5\Omega \]
Correct Answer: D
Solution :
\[{{R}_{eq}}=\frac{15\times 10}{25}+2+2r\]\[=8+2r\] \[i=\frac{3}{8+2r}\] \[2=i\,{{R}_{eq}}=\frac{3}{8+2r}\times 6\] \[16+4r=18\] \[\Rightarrow r=0.5\Omega \]You need to login to perform this action.
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