A) \[\left( -\frac{7}{17},\frac{6}{17} \right)\]
B) \[\left( -\frac{8}{17},\frac{2}{17} \right)\]
C) \[\left( -\frac{4}{17},\frac{1}{17} \right)\]
D) \[\left( -\frac{6}{17},\frac{10}{17} \right)\]
Correct Answer: B
Solution :
\[{{x}^{2}}-y+6=0\] \[2x-\left( \frac{y+10}{2} \right)+6=0\] \[4x-y-10+12=0\]centre of circle (- 4 , 2) \[\frac{x+4}{4}=\frac{y-2}{-1}=-\frac{(16-2+2)}{17}\] \[\left( \frac{-8}{17},\frac{2}{17} \right)\]You need to login to perform this action.
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