A) \[{{q}^{V}}\sqrt{\frac{Bd}{2m}}\]
B) \[Bd\sqrt{\frac{q}{2mV}}\]
C) \[\frac{B}{2}\sqrt{\frac{qd}{mV}}\]
D) \[\frac{B}{d}\sqrt{\frac{q}{2mV}}\]
Correct Answer: B
Solution :
Energy of proton \[=\frac{1}{2}m{{v}^{2}}=qV\] \[v=\sqrt{\frac{2qV}{m}}\] magnetic force \[=q\left( \vec{v}\times \vec{B} \right)=\frac{m{{v}^{2}}}{R}\] \[R=\frac{mv}{qB}\] \[\sin \alpha =\frac{d}{R}=\frac{dqB}{mv}=\frac{dqB}{m}\sqrt{\frac{m}{2qV}}\] \[\sin \alpha =Bd\sqrt{\frac{q}{2mV}}\]You need to login to perform this action.
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