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JEE Main & Advanced JEE Main Paper (Held On 10 April 2015)

  • question_answer
    You are asked to design a shaving mirror assuming that a person keeps it 10 cm from his face and views the magnified image of the face at the closest comfortable distance of 25 cm- The radius of curvature of the mirror would then be : JEE Main Online Paper (Held On 10 April 2015)

    A) -24 cm                  

    B)  24 cm

    C)  60 cm                  

    D)  30 cm

    Correct Answer: C

    Solution :

                     \[u=-10cm\] \[v=+15cm\] \[f=?\] \[\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\]     \[\frac{1}{15}-\frac{1}{10}=\frac{1}{f}=\frac{2}{R}\] \[-\frac{5}{150}=\frac{2}{R}\] \[R=-\frac{300}{5}=-60cm\]


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