A) 3
B) \[\frac{3}{2}\]
C) 2
D) \[\frac{5}{4}\]
Correct Answer: B
Solution :
\[\underset{x\to 0}{\mathop{Lim}}\,\frac{2x{{e}^{{{x}^{2}}}}+\sin x}{2\sin x\cos x}\] \[\underset{x\to 0}{\mathop{Lim}}\,\left( \frac{xx}{\sin x}{{e}^{{{x}^{2}}}}+\frac{1}{2} \right)\frac{1}{\cos x}=1+\frac{1}{2}=\frac{3}{2}\]You need to login to perform this action.
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