A) \[2\sqrt{2}\]
B) \[\sqrt{17}\]
C) \[\frac{5}{2}\sqrt{2}\]
D) \[\frac{3}{2}\sqrt{2}\]
Correct Answer: C
Solution :
Radius \[CP=\frac{4+1}{\sqrt{2}}\] \[=\frac{5}{\sqrt{2}}=\frac{5}{2}\sqrt{2}\] \[=\frac{dx}{{{\left( x-2 \right)}^{2}}}=-\frac{dt}{3}\] \[=\frac{-1}{3}\int_{{}}^{{}}{\frac{dt}{{{t}^{3/4}}}}=-\frac{1}{3}\int_{{}}^{{}}{t\frac{-3}{4}lt}\] \[=\frac{1}{3}\left[ \frac{{{t}^{\frac{-3}{4}+1}}}{\frac{-3}{4}+1} \right]\]\[=\frac{-4}{3}{{\left[ \frac{x+1}{x-2} \right]}^{1/4}}+c\]You need to login to perform this action.
You will be redirected in
3 sec