A) \[C{{u}^{2+}}\]
B) \[P{{b}^{2+}}\]
C) \[A{{s}^{3+}}\]
D) \[C{{o}^{2+}}\]
Correct Answer: D
Solution :
\[C{{o}^{+2}}\]ion is precipitated by \[{{H}_{2}}S\And N{{H}_{4}}OH\]present in group IV cationic Analysis
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