A) \[{{A}^{2}}-{{B}^{2}}{{C}^{2}}\]
B) \[\frac{A}{B}-C\]
C) \[\frac{C}{BD}-\frac{A{{D}^{2}}}{C}\]
D) \[\frac{(A-C)}{D}\]
Correct Answer: D
Solution :
(BD)\[AD=C\ell n(BD)\] \[(B)\,(D)\to \]dimensionless \[\left[ AD \right]=\left[ C \right]\] Checking options one by one \[\frac{A-C}{D}\]dimensions of A are not same as dimensions of C. Meaningless
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