JEE Main & Advanced
JEE Main Paper (Held On 10 April 2016)
question_answer
P and Q are two distinct points on the parabola, \[{{y}^{2}}=4x\], with parameters t and \[{{t}_{1}}\] respectively. If the normal at p passes through Q, then the minimum value of \[t_{1}^{2}\] is
JEE Main Online Paper (Held On 10 April 2016)
A)4
B)6
C)8
D)2
Correct Answer:
C
Solution :
\[{{t}_{1}}=-t-\frac{2}{t}\] \[t_{1}^{2}={{t}^{2}}+\frac{4}{{{t}^{2}}}+4\] min of \[t_{1}^{2}=8\]