A) \[41x+38y-38=0\]
B) \[41x-38y+38=0\]
C) \[41x+25y-25=0\]0
D) \[41x-25y+25=0\]
Correct Answer: B
Solution :
In cidene lines \[{{L}_{1}}+\lambda {{L}_{2}}=0\] \[(7x-y+1)+\lambda (y+2x-1)=0\] Let a point (1, - 1) on \[y+2x=1\] And image of (1, .1) lie on incidence line in\[7x-y-+1=0\] \[\frac{x-1}{1}=\frac{y+1}{-1}=\frac{-2(7+1+1)}{50}=x=\frac{-38}{25},\,\,\,\,y=\frac{-16}{25}\] \[\left( 7\left( \frac{-38}{25} \right)+\frac{16}{25}+1 \right)+\lambda \left( \frac{-16}{25}-\frac{76}{25}-1 \right)\] \[\lambda =\frac{-225}{117}\] \[(7x-y+1)\frac{-225}{117}(y+2x-1)=0\] \[369x-342y+342=0\] \[41x-38y+38=0\]You need to login to perform this action.
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