A) \[2\]
B) \[\frac{3}{4}\]
C) \[2\sqrt{2}\]
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
\[\sqrt{2x+1}=1+\sqrt{2x-1}\] Squaring on both sides \[2x+1=1+2x-1+2\sqrt{2x-1}\] \[1=2\sqrt{2x-1}\] \[1=4\sqrt{2x-1}\] \[x=5/8\] Now \[\sqrt{4{{x}^{2}}-1}\] at \[x=5/8\] = \[\sqrt{4\times \frac{25}{64}-1}=3/4\]You need to login to perform this action.
You will be redirected in
3 sec