A) Statement- I is false, but Statement-II is true.
B) Both the statements are false.
C) Both the statements are true.
D) Statement-I is true, but Statement-II is false.
Correct Answer: C
Solution :
\[{{A}^{2}}-5A+7I=0\,\left| \left. A \right|\pm 0 \right.\] \[\Rightarrow \,\,\,A-5I=-7{{A}^{-1}}\] \[\Rightarrow \,\,\,{{A}^{-1}}=\frac{1}{7}(5I-A)\] Hence statement 1 is true Now \[{{A}^{3}}-2{{A}^{2}}-3A+I=A{{(}^{2}}A)-3A+I\] \[=A(5A-7I)-2{{A}^{2}}-3A+I\] \[=3{{A}^{3}}-10A+I\] \[=5A-20I\,\,\,\,\,=3(5A-7I)-10A+I\] Statement 2 also correctYou need to login to perform this action.
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