A) 20 cm below flat surface
B) 30 cm below flat surface
C) 16 cm below flat surface
D) 14 cm below flat surface
Correct Answer: A
Solution :
\[\frac{1}{V}+\frac{1}{-4}=\frac{1}{-5}\] \[\frac{1}{V}+\frac{1}{4}-\frac{1}{5}=\frac{5-4}{20}\] \[V=20\,cm\] 1 acts as object for plane surface \[d'\frac{d}{{{n}_{rel}}}=\frac{30}{1.5}\] \[d'\frac{300}{15}=20\,cm\] 20 cm below plane surfaceYou need to login to perform this action.
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