A) 340 Hz
B) 170 Hz
C) 510 Hz
D) 680 Hz
Correct Answer: B
Solution :
5 beat sec \[{{F}_{air}}=\left( \frac{340}{340-5} \right)f\] \[{{f}_{\operatorname{i}nd}}=\left( \frac{340}{340+5} \right)f\] \[{{f}_{ind}}-{{f}_{air}}=5\] \[\left\{ \left( \frac{340}{340+5} \right)\left( \frac{340}{340+5} \right) \right\}f=5\] \[340\left\{ \frac{10}{(300-5)(340+5)} \right\}=5\] \[f=\frac{340\times 5}{10}\] \[f=170\,\,Hz\]You need to login to perform this action.
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