A) - 6.04
B) - 54.4
C) - 27.2
D) - 3.4
Correct Answer: A
Solution :
\[E=-13.6\frac{{{z}^{2}}}{{{n}^{2}}}\,eV\] \[\therefore \,\,E=-13.6\times \frac{{{2}^{2}}}{{{3}^{2}}}\,\] \[=-\,6.04\,\,eV\]
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