JEE Main & Advanced
JEE Main Paper (Held On 10-Jan-2019 Evening)
question_answer
Two sides of a parallelogram are along the lines,\[x+y=3\,\,\,\And \,\,x-y+3=0\]. If its diagonals intersect at (2, 4), then one of its vertex is-
[JEE Main Online Paper (Held On 10-Jan-2019 Evening]
A)(2, 1)
B)(2, 6)
C)(3, 5)
D) (3, 6)
Correct Answer:
D
Solution :
Slope of \[BC=1\] \[\Rightarrow \,\,\,\frac{3-h-5}{h-4}\,\,=\,\,1\,\,\Rightarrow \,\,h\,\,=\,\,1\,\,\,\Rightarrow \,\,B(1,\,\,2)\] Now, E is the mid-point of BD so D(3, 6)