A) \[{{H}_{2}}+B{{r}_{2}}\to 2HBr\]
B) \[{{H}_{2}}+C{{l}_{2}}\to 2HCl\]
C) \[{{H}_{2}}+{{F}_{2}}\to 2HF\]
D) \[{{H}_{2}}+{{I}_{2}}\to 2HI\]
Correct Answer: D
Solution :
\[{{H}_{2}}+{{I}_{2}}\rightleftharpoons \text{ }2HI\] In this reaction catalyst is required because \[{{I}_{2}}\] is a less reactive.You need to login to perform this action.
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