A) third
B) fourth
C) second
D) first
Correct Answer: C
Solution :
(BC and AD are perpendicular) \[\Rightarrow \,\,\frac{(k-2)}{h}\,=\,-\frac{4}{3}\,\,\Rightarrow \,3k\,-\,6\,=\,-4h\,\] \[\Rightarrow \,\,-12h-6=-4h\,\,\Rightarrow \,\,-6=8h\text{ }\Rightarrow \,\,h=-\frac{3}{4}\] \[\frac{k}{h}=-\,4\,\,\Rightarrow \,k=-\,4h\] \[k=-\,4\left( \frac{-3}{4} \right)\,\,\,\Rightarrow \,\,k=3\] \[B\left( \frac{-3}{4},\,\,3 \right)\]; IInd QuadrantYou need to login to perform this action.
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