A) 8.3 MeV energy will be released
B) energy of 11.9 MeV has to be supplied
C) energy of 12.4 MeV will be supplied
D) energy of 3.6 MeV will be released
Correct Answer: B
Solution :
\[{{E}_{supplied}}={{E}_{1}}=20\times B{{E}_{N}}\,of\,\,N{{e}^{20}}\] \[{{E}_{released}}=12\,\,B{{E}_{N}}\,of\text{ }{{C}^{12}}+2\times 4\times \,B{{E}_{N}}\,of\text{ }H{{e}^{4}}\] Supplied energy \[=20\,B{{E}_{N}}\,of\text{ }N{{e}^{20}}-12\times B{{E}_{N}}\] \[of\text{ }{{C}^{12}}-2\,\,\times \,\,4\times B{{E}_{N}}\,of\text{ }H{{e}^{4}}=11.9\text{ }MeV\]You need to login to perform this action.
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