A) 20
B) 25
C) -25
D) 13
Correct Answer: B
Solution :
\[C\left( -5,\,\,-6 \right)\] \[r=\sqrt{25+36-c}\] \[\cos 30{}^\circ \,\,=\,\,\frac{x}{r}\] \[\frac{\sqrt{3}}{2}\,=\,\frac{x}{r}\] \[\Rightarrow \,\,x\,\,=\,\,\frac{\sqrt{3}r}{2}\,\] side of triangle \[=\,\,\sqrt{3}r\] \[Area\,\,=\,\,\frac{\sqrt{3}}{4}{{(\sqrt{3}r)}^{2}}\] \[\frac{3\sqrt{3}}{4}{{r}^{2}}\,=\,27\sqrt{3}\] \[\Rightarrow \,\,\,{{r}^{2}}\,\,=\,\,36\] \[\Rightarrow \,\,\,25+36-c=36\] \[\Rightarrow \,\,\,c=25\]You need to login to perform this action.
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