A) \[\frac{11}{12}\,L\]
B) \[\frac{13}{24}\,L\]
C) \[\frac{5}{12}\,L\]
D) \[\frac{11}{24}\,L\]
Correct Answer: B
Solution :
y = Potential gradient \[=\,\,\,\frac{1R}{L}\] \[=\,\,\,\frac{\varepsilon }{12r+r}\,\,=\,\,\frac{12r}{L}\] \[=\,\,\,\frac{12}{13}\,\,\frac{\varepsilon }{L}\] At balanced condition emf of cell \[=\,\,y\ell \] \[\frac{\varepsilon }{2}=\,\,\frac{12}{13}\,\,\frac{\varepsilon }{L}\,\times \ell \] \[\ell \,\,=\,\frac{13}{24}\,L\]You need to login to perform this action.
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