A) \[s{{p}^{3}}d\] and 2
B) \[s{{p}^{3}}{{d}^{2}}\] and 2
C) \[s{{p}^{3}}d\] and 1
D) \[s{{p}^{3}}{{d}^{2}}\] and 1
Correct Answer: D
Solution :
Number of b.p. = 5 Number of l.p. = 1 Sp3d2 = hybridisationYou need to login to perform this action.
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