A) 400 mV
B) 200 mV
C) 4 mV
D) 0.4 mV
Correct Answer: A
Solution :
Given: No. of turns N = 1000 Face area, \[A=4c{{m}^{2}}=4\times {{10}^{-4}}{{m}^{2}}\] Change in magnetic field, \[\Delta B={{10}^{-2}}wb{{m}^{-2}}\] Time taken, t\[t=0.01s={{10}^{-2}}\sec \] Emf induced in the coil e = ? Applying formula, Induced emf, \[e=\frac{-d\phi }{dt}\] \[=N\left( \frac{\Delta B}{\Delta t} \right)A\cos \theta \] \[=\frac{1000\times {{10}^{-2}}\times 4\times {{10}^{-4}}}{{{10}^{-2}}}=400mV\]You need to login to perform this action.
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