A) \[\text{23}\text{.03cal}\,\text{de}{{\text{g}}^{\text{-1}}}\]
B) \[\text{-23}\text{.03cal}\,\text{de}{{\text{g}}^{\text{-1}}}\]
C) \[\text{2}\text{.303cal}\,\text{de}{{\text{g}}^{\text{-1}}}\]
D) \[\text{-2}\text{.303cal}\,\text{de}{{\text{g}}^{\text{-1}}}\]
Correct Answer: B
Solution :
Given, \[{{C}_{p}}=10\] cals at 1000 K \[{{T}_{1}}=1000K.{{T}_{2}}=100K\] \[m=32g\] \[\Delta S=?\]at constant pressure \[\Delta S={{C}_{p}}\ln \frac{{{T}_{2}}}{{{T}_{1}}}\] \[=2.303\times {{C}_{p}}\log \frac{{{T}_{2}}}{{{T}_{1}}}\] \[=2.303\times 10\log \frac{100}{1000}\]\[=-23.03cal\,{{\deg }^{-1}}\]You need to login to perform this action.
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